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当形参、实参是指针变量...

published at 2022-11-16
c & c++ pointer

《一个有关指针传参的问题》,再理一理这里边的一些问题…

在单向值传递的过程中,我们知道,形参是对实参的值的拷贝。在实参的值传递给形参后,对形参的一切操作,都不会对实参产生什么影响。比如下边这串代码:

#include <iostream>

using namespace std;

void func(int n);

int main()
{
    int n = 5;
    cout << "Before func(), main(): n = " << n << endl;
    func(n);
    cout << "After func(), main(): n = " << n << endl;
    return 0;
}

void func(int n)
{
    cout << "Before n++, func(): n = " << n << endl;
    n++;
    cout << "After n++, func(): n = " << n << endl;
}

下边是输出结果:

Before func(), main(): n = 5
Before n++, func(): n = 5
After n++, func(): n = 6
After func(), main(): n = 5

通过打印它们的地址,我们也可以认识到这一点:

#include <iostream>

using namespace std;

void func(int n);

int main()
{
    int n = 5;
    cout << "In main(): " << endl;
    cout << "n = " << n << endl;
    cout << "&n = " << &n << endl;
    cout << endl;
    func(n);
    return 0;
}

void func(int n)
{
    cout << "In func(): " << endl;
    cout << "n = " << n << endl;
    cout << "&n = " << &n << endl;
}

/*
输出结果:

In main():
n = 5
&n = 0x61fe1c

In func():
n = 5
&n = 0x61fdf0
*/

如果把变量类型从普通类型变成指针类型,那么类似的,发生的其实也是一次值传递,也即,指针变量的值发生了一次拷贝,请看下边的例子:

#include <iostream>

using namespace std;

void func(int *p);

int main()
{
    int *p = new int;
    cout << "In main(): " << endl;
    cout << "p = " << (int *)p << endl;
    cout << "&p = " << &p << endl;
    cout << endl;
    func(p);
    return 0;
}

void func(int *p)
{
    cout << "In func(): " << endl;
    cout << "p = " << (int *)p << endl;
    cout << "&p = " << &p << endl;
}

在我电脑上的输出结果是:

In main():
p = 0xee61c0
&p = 0x61fe18

In func():
p = 0xee61c0
&p = 0x61fdf0

可以看到,int * 类型的指针变量 p 的值是相同的,但地址不同,这是两个变量。

把上边代码 main() 中的 p 记为 p1func() 中的记为 p2,那么就可以这样理解为,当调用 func() 时,p2p1 指向了相同的位置,但它们确实不是同一个指针

对于《一个有关指针传参的问题》中的那段错误代码,其实错误就是,在函数中 new 出来内存后,只是让形参指向了那片内存,而原来的实参并没有同步地指过去。

但是只要确定形参的指针和实参的指针指向的地址是相同的,那么对这同一片内存进行的操作,就是同步的,比如:

#include <iostream>

using namespace std;

void func(int *p);

int main()
{
    int *p = new int;
    *p = 5;
    cout << "Before func(), main(): (*p) = " << *p << endl;
    func(p);
    cout << "After func(), main(): (*p) = " << *p << endl;
    return 0;
}

void func(int *p)
{
    cout << "Before (*p)++, func(): (*p) = " << *p << endl;
    (*p)++;
    cout << "After (*p)++, func(): (*p) = " << *p << endl;
}

输出结果:

Before func(), main(): (*p) = 5
Before (*p)++, func(): (*p) = 5
After (*p)++, func(): (*p) = 6
After func(), main(): (*p) = 6

由于数组名其实就是数组第一个元素(下标为 0 的那个元素)的地址,所以类似的,在函数中对数组形参的操作会等效到数组实参上去:

#include <iostream>

using namespace std;

void func(int[], int);

int main()
{
    int a[3] = {0, 1, 2};
    for (int x : a)
        cout << x << " ";
    cout << endl;
    func(a, 3);
    for (int x : a)
        cout << x << " ";
    return 0;
}

void func(int arr[], int n)
{
    for (int i = 0; i < n; i++)
        arr[i]++;
}

输出结果:

0 1 2
1 2 3